# Dipole Moment

Griffith' E&M problem 3.28 page 151

Given a spherical surface of radius R which carries a surface charge $\simga = k \cos\theta$

Calculate the dipole moment of this charge distribtuion

well using this equation

$$\vec{p} = \int \vec{r'} \sigma(\theta') dA' = \int Rk \cos\theta R^2 \sin\theta d\theta d\phi$$

but i was told that this setup is wrong that - tat the first term in the integration which i have as R should be $R \cos\theta$ why is that??

what about my area element is that correct?

OlderDan
Homework Helper
A simple dipole moment of two charges is the magnitude of the charge times the distance between them pointing from negative to positive. Taken from their center of charge that would be the sum of the products of the charges times the position vector from the center. You are adding a bunch of charges that are positive in the upper half space and negative in the lower half with cylindrical symmetry. You need the z coordinates of each bit of charge times the charge. The z coordinate is R*cosθ. The area element is OK.

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A simple dipole moment of two charges is the magnitude of the charge times the distance between them pointing from negative to positive. Taken from their center of charge that would be the sum of the products of the charges times the position vector from the center. You are adding a bunch of charges that are positive in the upper half plane and negative in the lower half with cylindrical symmetry. You need the z coordinates of each bit of charge times the charge. The z coordinate is R*cosθ. The area element is OK.

that makes sense now thanks!

do you have griffith's textbook
what do you think are 'good' questions to do in the 'more problem' section for chapter 3?
15 questions seems rather arduous since i would liek to go onto chapter 4...

OlderDan