A molecule of water has a dipole moment of 6.1×10–30 C m. Calculate the difference in potential energy between when its dipole is parallel to an electric field of 2.0×105 V m–1 and when it is anti-parallel to the field.
The Attempt at a Solution
If the charge on each side of the dipole is just 1.6x10-19 ill be able to do the problem i think. other than that i have no idea what to do.
i was guna divide the dipole moment by 1.6x10-19 to give me the diameter of the molecule. then just use U=kq1q2/r
Help me please and add any helpful infomation