Dipole operator question

  • #1

Main Question or Discussion Point

Hi,

In quantum optics, when we talk about atom field interaction with a classical field and quantized atom, we say that the Hamiltonian has an interaction part of the form [itex]\hat{d}.\vec{E}[/itex] where d is the dipole operator.

For a two level atom, the dipole operator has only off diagonal elements and these are of the form [itex]\langle g\mid\hat{d}\mid e\rangle[/itex]. Now, this expectation value still has a direction because we take its dot product with the polarization direction of the electric field. But, in any atom, both g and e are spherically symmetrical states so what "direction" is being talked about here?

Thank you :)
 

Answers and Replies

  • #2
34,295
10,328
If both g and e have a spherical symmetry (=> S-states), the dipole expectation value should be 0. You need an odd ##\Delta l## to get a non-zero expectation value - one symmetric and one antisymmetric wave function, I think.
 
  • #3
Thank you mfb.

Pardon me if this is a silly question, I just revised the angular quantum number section of my QM text. I understand that if we are talking about states with nonzero l, then they are not spherically symmetric, correct? If so, what determines the asymmetry? For instance, how do which direction the p oribital's dumbell points along?

Also, when we talk about the emission of a photon, does this asymmetry also determine the direction of the photon? That is, there is a higher probability of emission in some directions compared to others?

Thank you.
 
Last edited:

Related Threads on Dipole operator question

  • Last Post
Replies
3
Views
15K
Replies
3
Views
843
Replies
6
Views
4K
Replies
2
Views
1K
Replies
0
Views
2K
Replies
4
Views
2K
  • Last Post
Replies
5
Views
4K
  • Last Post
Replies
3
Views
570
Replies
1
Views
771
  • Last Post
Replies
0
Views
972
Top