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## Main Question or Discussion Point

Hi this is my first post here so I'm sorry if my question seems trivial.

I haven't worked a lot with the dirac delta function before, so i always thought that the shifting property would only work as:

[tex]\int\delta(x-h)\;f(x)\;dx=f(h)[/tex]

Now I've been reading some articles and I came across expressions like:

[tex]\int\delta(h-x)\;f(x)\;dx=f(h)[/tex]

which didn't make sense to me so I checked on the internet and saw that the delta function is supposed to be an even function.

Now I know it is not entirely a true function, but still the only description I know is that it's zero everywhere except for x. If I can give values to x other than zero, than

[tex]\delta(x)=\delta(-x)[/tex] means for example

[tex]\delta(5)=\delta(-5)[/tex] which doesn't make sense to me.

So I'll be very glad if someone can explain to me why it's an even function.

Thanks!

I haven't worked a lot with the dirac delta function before, so i always thought that the shifting property would only work as:

[tex]\int\delta(x-h)\;f(x)\;dx=f(h)[/tex]

Now I've been reading some articles and I came across expressions like:

[tex]\int\delta(h-x)\;f(x)\;dx=f(h)[/tex]

which didn't make sense to me so I checked on the internet and saw that the delta function is supposed to be an even function.

Now I know it is not entirely a true function, but still the only description I know is that it's zero everywhere except for x. If I can give values to x other than zero, than

[tex]\delta(x)=\delta(-x)[/tex] means for example

[tex]\delta(5)=\delta(-5)[/tex] which doesn't make sense to me.

So I'll be very glad if someone can explain to me why it's an even function.

Thanks!