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Dirak notation question

  1. Feb 12, 2014 #1
    I have the following question for anyone who can help:
    Suppose in Dirak notation i have the following state:
    /ψ> = 2 /u1> + /u2> where /u1>,/u2> are the two first eigen kets of energy of the infinite square well.

    That means <x/u1>= Asin(π x /L) and <x/u1>= Asin(2 π x /L) which gives :

    <x/ψ>= 2Asin(π x /L) + Asin(2 π x /L)

    Everything ok so far. But what would happen if i chose <x/u1>= - Asin(π x /L) instead of
    <x/u1>= Asin(π x /L) which is perfectly legitimate. Then <x/ψ> would become:

    <x/ψ>= -2Asin(π x /L) + Asin(2 π x /L) which is not the same as

    <x/ψ>= 2Asin(π x /L) + Asin(2 π x /L) ..( you can not get to one another by multiplying a constant phase so the are different)
    So the question is does /ψ> = 2 /u1> + /u2> determine the state of a system or not because it seems that it depends on my free choice of base kets /u1>, /u2> ?
     
  2. jcsd
  3. Feb 12, 2014 #2
    Yes, that's correct. Any change to the phase of /u1> must be matched with another phase to the coefficients of the expansion of /ψ>, otherwise you will get a different state.
     
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