1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Direct Stiffness Method for a distributed load

  1. Apr 20, 2017 #1
    I'm working on a question which asks to determine the deflection, curvature, forces and moments of a simply supported beam with a distributed load. diagram shown in here http://imgur.com/a/wpI4k

    Initially, I've done the calculation with 1 plane beam element with 2 nodes. At L = 0 and L = 3. But that doesn't give me the deflection of the beam at L = x/2.

    So I'm trying to use 2 elements with 3 nodes as shown here.

    I've reduced the matrix down to a 4 x 4 with {theta_1; v_2; theta_2; theta_3} as unknowns.

    The result i got were:

    • theta_1 = -0.0462
    • v_2 = -0.0865
    • theta_2 = 0
    • theta_3 = 0.0462
    The results from the 2 node analysis were:

    • Q_1 = 3N
    • theta_1 = -0.0231
    • Q_2 = 3N
    • theta_2 = 0.0231
    Which do not agree with the results from the 3 node analysis.

    Moreover, from using the Euler beam equation I calculated a deflection result of -21.6mm which does not agree with v_2 either.

    Because of the difference in values, I got from the 3 node analysis, I have yet to substitute the values back in to calculate the other nodal values.

    Did I make a mistake?

    Is it correct to use L/2 instead of L for my three node equivalent loads?

    i.e. -w(L/2)/2 instead of -wL/2 as was the case in the 2 node analysis.
  2. jcsd
  3. Apr 25, 2017 #2
    Thanks for the thread! This is an automated courtesy bump. Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post? The more details the better.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted