1. The problem statement, all variables and given/known data http://img6.imageshack.us/img6/4041/meprob210.jpg [Broken] This was a plate with two bars attached / coming out of it (A and B, represented by Fa and Fb, respectively). The question says: Determine the angle of θ for connecting member A to the plate so that the resultant force of Fa and Fb is directed horizontally to the right. Also, what is the magnitude of the resultant force? 2. Relevant equations law of sines, trig components, 3. The attempt at a solution So going by that, then θ should be 0 since it's horizontally to the right. So solving for the red θ above: 0 = tan-1(Fy/Fx), 0 because of the resultant being directed along the right horizontal axis. Fx = (8kcos θ) + (6kcos (-50)) Fy = (8ksin θ) + (6ksin (-50)) 0 = tan-1( [(8ksin θ) + (6ksin (-50))]/[ (8kcos θ) + (6kcos (-50))] ) tan-1(0) = 0 so 0 = (8ksin θ) + (6ksin (-50))/(8kcos θ) + (6kcos (-50)) and then 0 = (8ksin θ) + (6ksin (-50)) then θ = sin-1(4596/8000) and I get θ = 35 degrees but this isn't the given answer. Did I do something wrong?