- #1

- 75

- 0

However, this plane equation can also be rewritten as (-A)x + (-B)y + (-C)z + (-D) = 0, in which case the normal vector is (-A, -B, -C) which is in the opposite direction as the other normal vector.

Basically my question is this - what's the direction of a normal vector - i.e. both directions seem correct.