a thin nonconducting rod is bent in a circular arc. Half is given a uniformly distributed postive charge and the other half uniformly negative. Draw the direction of the electric field at the center of the circle.
E=Fe/qo, F=qE E=ke(q/r2)r
The Attempt at a Solution
Im not really sure what to apply here, a test particle is always postive, so if placed in the middle of the circle made by the bended rod it the electric field points to the negative side....