Hi I'm having a hard time understanding the direction of the shift of the Fermi level in a pn-junction device upon application of a bias. Consider the device to be p-type on the left side and n-type on the right side, where the right side is grounded. From Pierret, Semiconductor device fundamentals, p. 221 "One progresses from the equilibrium diagram to the forward bias diagram by moving the n-side upwards by qV_A while holding the p-side fixed." Why "upwards" when under forward bias? How can I picture this to myself? Thanks for hints.