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Direction of phasor, CCW vs CW

  1. Jul 10, 2013 #1
    1. The problem statement, all variables and given/known data
    Hi

    Circularly polarized light we can describe by a vector [itex]v=(1,\pm i)[/itex], where the sign on the phase i describes which way the phasor turns (CCW or CW). I am confused about what sign belongs to which direction.

    Is there a neat way to determine this?
     
  2. jcsd
  3. Jul 12, 2013 #2

    tiny-tim

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    come on, guys! :wink:

    somebody must have a clever way of memorising this! :smile:
     
  4. Jul 14, 2013 #3
    I think the right-hand rule applies here, so (1, +i) is CCW and (1, -i) is CW.
     
  5. Jul 14, 2013 #4

    tiny-tim

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    i can never remember which way round it is, i have to look it up each time :redface:

    (so, sorry, obviously i can't recommend a good way of remembering it!)
     
  6. Jul 14, 2013 #5

    TSny

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