# Direction of phasor, CCW vs CW

1. Jul 10, 2013

### Niles

1. The problem statement, all variables and given/known data
Hi

Circularly polarized light we can describe by a vector $v=(1,\pm i)$, where the sign on the phase i describes which way the phasor turns (CCW or CW). I am confused about what sign belongs to which direction.

Is there a neat way to determine this?

2. Jul 12, 2013

### tiny-tim

come on, guys!

somebody must have a clever way of memorising this!

3. Jul 14, 2013

### Niles

I think the right-hand rule applies here, so (1, +i) is CCW and (1, -i) is CW.

4. Jul 14, 2013

### tiny-tim

i can never remember which way round it is, i have to look it up each time

(so, sorry, obviously i can't recommend a good way of remembering it!)

5. Jul 14, 2013