A constant potential is maintained across a parallel plate capacitor. A dielectric slab is slowly inserted between the plates (width of slab=distance between the plates). What will the direction of force applied by capacitor on dielectric be?
The Attempt at a Solution
I went through the derivation and followed it logically for the magnitude of the force = 0.5*(epsilon)(L)(k-1)(V^2)/d where L is length of plate, k is relative permitivitty of dielectric, V is potential and d is distance between plates. I can't figure out what the direction of this force will be though...In case of a isolated capacitor, the force would have pulled the slab inside. I'd appreciate insight, thank you