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Direction of vector potential

  1. Mar 2, 2007 #1
    We know in all ordinary cases the direction of vector potential will be mimic to the direction of current.As it is evident from the expression of A=(mu/4*pi) int{J /(r-r')}dV which is valid only for finite current distributions.
    But in example 5.12 and in exercise 5.25 Griffiths has given situations where current distributions extend upto infinity.But,still the direction of A is the same as direction of J .Can you help me to reconcile these two apparently contrasting views?
  2. jcsd
  3. Mar 2, 2007 #2
    You do know it is gauge dependent, right (The formula you brought works for Coulomb)? I don't know about the example you talked about.
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