(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A new circus act is called the Texas Tumblers. Lovely Mary Belle swings from a trapeze, projects herself at an angle of 53 ^\circ, and is supposed to be caught by Joe Bob, whose hands are 6.1 {\rm m} above and 8.2 {\rm m} horizontally from her launch point (the figure ). You can ignore air resistance.

For the initial speed calculated in part A, what is the direction of her velocity when Mary Belle reaches Joe Bob?

Additionally I have v_0 is 14 m/s, v=8.4 m/s, v_x= 8.42, v_y=1.17

2. Relevant equations

Im using arctan=(v_y/v_x) which gives me 7.9 degrees which is wrong

3. The attempt at a solution

arctan=(v_y/v_x) which gives me 7.9 degrees which is wrong

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# Homework Help: Direction of velocity

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