(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A particle is projected from the top of a vertical cliff with a speed of 40 m/s at an angle of elevation of 45 degrees towatds the sea . The particle hits the surface of the sea at a point whose horizontal distance from the cliff is 200 m . Find the direction of the velocity of the particle when it hits the surface of the sea . [Take g=10 m/s^2]

2. Relevant equations

3. The attempt at a solution

For horizontal motion ,

s=vt

200=40 cos 45 t

t=5 root (2)

For vertical motion ,

v=u+at

v=40 sin 45 -10(5 root 2)

=-(60)/(root 2)

This is the magnitude and i hv no idea how to find its direction

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# Homework Help: Direction of velocity

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