1. I know this is really simple but I'm missing some little piece of the puzzle No problem getting to vab= +1.5V for a) +1.5V for b)i. -2.5V vor b)ii. +0.5V for b)iii. But what about current I? 2. I=V/R 3. so for IR2 b)i. I have 1.5V/1kΩ=1.5mA (sure I agreee with that) b)ii. I have -2.5V/1kΩ=-2.5mA (hmmm) b)iii. I have 0.5V/1kΩ=0.5mA does b)ii. make sense? If the voltage is reversed to -5V does the current also reverse? What if I just chose to draw the arrow for current the other way round? How do I account for that when analysing the circuit? Really simple I know, but it's doing my head in!