How would I find the direction vector of a line given in the form ax + by + cz +d =0?
I see an equation of a plane, not a line.
Damn, sorry, got carried away with my letters. I meant ax + by +c = 0. Sorry about that...
For a line, (1,m) is always a directional vector where m is the slope. Can you find the slope?
Yeah - I thought it would be something simple like that. Thanks for your help.
Thanks for asking that Q, it helped me too
I don't think there's a need to thank someone who started a thread two years ago and have not posted since.
LORL.... Thanks for pointing that out. ( At least you still logon)
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