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Discharge of capacitor question
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[QUOTE="Goddar, post: 4987012, member: 134780"] Hi. For (i) i think since the charges are accelerated (by the E-field) along the z-direction that doesn't contribute to the wire's momentum (there are forces on the plates but they cancel if the plates are fixed). For (ii), it seems that by symmetry the E-field created by the changing B-field should only have components along the y-axis (think about what B-field two parallel current sheets would create if currents in the sheets ran in the y and –y direction); but in any case we still have to assume the plates are fixed in the z-direction since otherwise the constant E-field would bring them together and the problem would get more complicated... So the changing B-field would produce: [B]E[/B] (z) = (z/c)[B]j[/B] ∫dt B(t) , and the total impulse would be: ΔP = qΔE = qB(0)d/c = EBAd/c as advertised [/QUOTE]
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Discharge of capacitor question
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