1. The problem statement, all variables and given/known data Two test charges are located in the x–y plane. If q1 = -3.50 nC and is located at x = 0.00 m, y = 0.680 m and the second test charge has magnitude of q2 = 3.60 nC and is located at x = 1.00 m, y = 0.650 m, calculate the x and y components, Ex and Ey, of the electric field, , in component form at the origin, (0,0). The Coulomb Force constant is 1/(4π ε0) = 8.99 × 109 N·m2/C2. 2. Relevant equations E=Kq/r^2 3. The attempt at a solution So first I converted all of the given data. q1= -3.5x10^-9 C q2= 3.6x10^-9 C r1=.680 r2=sqrt(1.1926) angle=33degrees using tan^-1(.650/1) Then I solved for E1y since it is entirely in the y direction: E1y= K(-3.5x10^-9)/(.680)^2= -68.05 Then solved the x and y components of E2 E2x= K(3.6x10^-9)/(1.1926)^2(cos(33)) = 22.76 E2y= K(3.6x10^-9)/(1.1926)^2(sin(33))= 14.78 Then: E1y+E2y E2x This is my newest answer that I've come up with but all of them have been wrong. I'm not sure what I'm missing or what's going wrong.