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Discrete Mathematics

  1. Sep 17, 2008 #1
    I know I have to write an equation to solve the problem down. But I realy don't know how to use the given information. I did it by enumeration, but I don't get it how this will be shown by an algebriac argument. Please some one help me at least with an idea.

    If S = {1,2,3,4}, consider the function f:SxS-> N defined by f(x,y)= 4x+y-4. Determine the image of f, and show by an algebraic argument [not by enumeration] that f is one to one function on SxS. [hint: because S has only four elements, the difference of two of its elements is a multiple of 4 iff they are equal.]
  2. jcsd
  3. Sep 17, 2008 #2


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    f(x1,y1)-f(x2,y2)=4(x1-x2)+(y1-y2). This can be 0 if and only if x1=x2 and y1=y2.

    4(x1-x2) is ALWAYS a multiple of 4, while (y1-y2) cannot be a multiple of 4 unless y1=y2.
  4. Sep 18, 2008 #3
    Thank you so much. I get it now.
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