- #1

- 72

- 0

Is it time varying ?

I proceeded as follows

x[n] → x[n]^2

x[n+a] → x[n+a]^2

so y[n+a] = x[n+a]^2

So according to me it is time invariant

Am i right ?

- Thread starter erece
- Start date

- #1

- 72

- 0

Is it time varying ?

I proceeded as follows

x[n] → x[n]^2

x[n+a] → x[n+a]^2

so y[n+a] = x[n+a]^2

So according to me it is time invariant

Am i right ?

- #2

- 11

- 0

ya ... it is a non-linear time-invariant system

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 4

- Views
- 1K

- Last Post

- Replies
- 1

- Views
- 2K

- Last Post

- Replies
- 2

- Views
- 5K

- Last Post

- Replies
- 1

- Views
- 850

- Last Post

- Replies
- 2

- Views
- 2K

- Last Post

- Replies
- 0

- Views
- 5K

- Replies
- 2

- Views
- 522

- Replies
- 0

- Views
- 835

- Replies
- 3

- Views
- 4K