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Ok this is the first question:
1) Find the set of values of k for which the equation: f(x)=x2-kx+16 has no real solutions.
This is what I've done:
discriminant < 0
k2-4(16) =0
K2-64=0
k=8
x2-8x+16
(x-4)(x-4)=0
x=4
But, i don't know what to do next now! Please help!
2) The quadratic equation kx2+(4k+1)x +(3k+1)=0 has a repeated root. find the value of k.
I'm not at all sure about this one, but i tried to do something anyway:
(4kx+x)2 -12k2+4k=0
4kx +x -10k = 0
(2k+x)(2x-5) =0
I have no idea what i'm doing, please help!
Thanks!
1) Find the set of values of k for which the equation: f(x)=x2-kx+16 has no real solutions.
This is what I've done:
discriminant < 0
k2-4(16) =0
K2-64=0
k=8
x2-8x+16
(x-4)(x-4)=0
x=4
But, i don't know what to do next now! Please help!
2) The quadratic equation kx2+(4k+1)x +(3k+1)=0 has a repeated root. find the value of k.
I'm not at all sure about this one, but i tried to do something anyway:
(4kx+x)2 -12k2+4k=0
4kx +x -10k = 0
(2k+x)(2x-5) =0
I have no idea what i'm doing, please help!
Thanks!