Ok this is the first question: 1) Find the set of values of k for which the equation: f(x)=x2-kx+16 has no real solutions. This is what I've done: discriminant < 0 k2-4(16) =0 K2-64=0 k=8 x2-8x+16 (x-4)(x-4)=0 x=4 But, i don't know what to do next now! Please help! 2) The quadratic equation kx2+(4k+1)x +(3k+1)=0 has a repeated root. find the value of k. I'm not at all sure about this one, but i tried to do something anyway: (4kx+x)2 -12k2+4k=0 4kx +x -10k = 0 (2k+x)(2x-5) =0 I have no idea what i'm doing, please help! Thanks!