I'm at a loss here. I have no idea how to prove this.(adsbygoogle = window.adsbygoogle || []).push({});

For all positive integers, k, m, n if k|mn then k|4m or k|4n.

2. Relevant equations

An integer r is divisible by an integer d if and only iff r=ds where s is some integer and d != 0.

3. The attempt at a solution

I tried rewriting the divisibilities.

k|4m

4m = ks

k|4n

4n = kq

k|mn

mn = ky

but I don't know where to go from here.

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Disibility proof

**Physics Forums | Science Articles, Homework Help, Discussion**