1. The problem statement, all variables and given/known data A person going for a walk follows the path shown in the figure, where y1 = 290 m and θ = 61.0°. The total trip consists of four straight-line paths. At the end of the walk, what is the person's resultant displacement measured from the starting point? ____ m? ____ degrees? (from the + x axis) 2. Relevant equations http://img257.imageshack.us/img257/3813/physicsho5.th.jpg [Broken] 3. The attempt at a solution I've calculated and found the correct angle, which is 238.08 degrees but I don't know why I keep getting the wrong magnitude. I got 216.45 m and it's incorrect. here is my work: vector A = 100N @ 0 degrees ; A_x = 100 A_y = 0 vector B = 290N @ 270 degrees; B_x = 0 B_y = -290 vector C = 150N @ 210 degrees; C_x = -129.90 C_y = -75 vector D = 200N @ 115 degrees; D_x = -84.52 D_y = 181.26 ____________________________________________________ F_x = -114.42; F_y = -183.74 tan^-1 (-183.74/-114.42) = 58.1 degrees + 180 degrees = 238.08 degrees so for the magnitude I did -114.42^2 + -183.74^2 = c^2 sq root of 46852.3 ... or 216.454 = c but that is wrong, can anyone tell me what c would be? thanks.