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Displacement and rotation

  1. May 6, 2007 #1
    A beam AB has constant EI and u(x) describes the deformation:

    http://www.badongo.com/pic/625051

    The first task here is to show that there's no displacement or rotation at A. For the case of the displacement, I guess I can do that simply by replacing x with 0 in the u(x)-equation?

    But how about the rotation? What is meant by that? Is it the same as slope?
     
    Last edited: May 6, 2007
  2. jcsd
  3. May 6, 2007 #2

    Pyrrhus

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    Yes and yes the first derivative du(x)/dx is the rotation or slope (Remember that for small angles [itex] \tan \theta \approx \theta [/itex])
     
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