1. The problem statement, all variables and given/known data A 0.24 kg mass is suspended on a spring which stretches a distance of 5.9 cm. The mass is then pulled down an additional distance of 13.5 cm and released. What is the displacement from the equilibrium position with the mass attached (in cm) after 0.46 s? Take up to be positive and use g = 9.81 m/s2. 2. Relevant equations Hint: Get k from the displacement as it was done in this example. The equation will have ω = (k/m)1/2, and the phase will be such that it will be a cosine with a negative amplitude, because it starts at a negative displacement. Be careful about the sign! You have to get y=-x*cos(sqrt(t^2*g/x)) where from the eq-position it follows that omega=sqrt(g/x) 3. The attempt at a solution I tried doing the equations stated above however, I am still confused. I was not sure if x means the distance the spring stretches at first or what? Also if X would then be the initial spring stretch + the extra distance pulled or what? Any help would be must appreciated!