(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A pulley fixed to a rigid support carries a rope whose one end is tied to a ladder with a man and the other end to a counterweight of mass M. The man of mass m climbs up a distance h with respect to the ladder and then stops. If the mass of the rope and the friction in the pulley axle are negligible, find the displacement of the centre of mass of this system.

2. Relevant equations

COM[itex]_{y}[/itex]=my[itex]_{1}[/itex]+my[itex]_{2}[/itex]/m+M

3. The attempt at a solution

Let the y-coordinate of man be l and that of mass M be 0. Since it goes up a height h

∴ y-coordinate of the man changes to (l+h) but that of mass M remains unchanged.

So, if I subtract the final COM from initial COM I get the answer mh/m+M. But the correct answer is mh/2M. I'm unable to bring out mistake in my solution.

**Physics Forums - The Fusion of Science and Community**

# Displacement of centre of mass

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

Have something to add?

- Similar discussions for: Displacement of centre of mass

Loading...

**Physics Forums - The Fusion of Science and Community**