- #1

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- Homework Statement
- The displacement of a particle moving in straight line is given by ##s=6+12t-2t^2##. The distance covered by particle in first 5sec. Units are in meters and sec.

- Relevant Equations
- ##v=\frac{ds}{dt}##

I calculated v=0 at t=3. s(3) =24 m. s(5)=16 m. So reverse distance that the particle travelled=24-16=8 m. So total distance =24+8=32 m.