aaquib said:A train travels 58km at an average velocity of 77km/h[E] waits for 5min, and then runs for half an hour at an average velocity of 64km/h[E]. Find the total displacement.
HOW?!?? I am so confused. I have a test tomorrow and my teacher is useless. Please help me pass this course.
kdv said:You shoudl know that aevrage velocity is given by
[tex] \overline{v}_x = \frac{\Delta x}{\Delta t} [/tex]
so if you have the time and the average velocity you may find the displacement. Find the displacements for each of the two different intervals and simply add them up. That's really that simple.
aaquib said:I only have the time for the second part though. It doesn't tell me how long it travels for until after it stops.
The displacement problem refers to the difference between the original position of an object and its final position after it has moved or been displaced.
Understanding displacement is important in science because it helps us measure the distance an object has moved and calculate its velocity, acceleration, and other important physical quantities.
Displacement can be caused by a variety of factors, such as forces acting on an object, changes in temperature or pressure, or the movement of other objects in its surroundings.
Displacement is a vector quantity that takes into account both the magnitude and direction of an object's change in position, while distance is a scalar quantity that only measures the total length of the path an object has traveled.
Yes, displacement can be negative if an object moves in the opposite direction of its initial position. This indicates that the object has moved in the opposite direction of the positive direction, or the direction of the coordinate system being used.