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Displacement Problems

  1. Aug 24, 2009 #1
    1. The problem statement, all variables and given/known data
    A rocket starts from rest and accelerates for 3.50 s with an acceleration of 5.00 m/s². If it continues to rise until its velocity is zero, what will be its maximum height?


    2. Relevant equations
    I thought I had to use the "UNIFORM MOTION with CONSTANT ACCELERATION" formula, which is d=vi*t+(1/2)*a*t²
    d = distance
    vi = initial velocity
    t = time
    a = acceleration


    3. The attempt at a solution
    d = 0*3.5+(1/2)(5.00 m/s²)(3.5)²

    I am not sure whether I set up the problem correctly or not.
     
  2. jcsd
  3. Aug 24, 2009 #2

    drizzle

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    hey cyspope,
    what's the velocity of the rocket after 3.50 s? use this velocity* to determine the extra displacement, [this will be the initial velocity vo], you may use the velocity & displacement equation.



    * note the rocket will be decelerating under the effect of g = 9.8 m/s2 till the velocity reaches zero.
     
  4. Aug 24, 2009 #3
    It doesn't says about the velocity of the rocket after 3.50 s. and How would you apply the gravity, which is 9.8 m/s² into the equation?
     
  5. Aug 24, 2009 #4

    drizzle

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    hint:

     
  6. Aug 24, 2009 #5

    drizzle

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    don't forget, there're two different displacements, d1 [which you can calculate using the first part of the question], and d2 [as described above]. the maximum displacement [height] is then d1+d2
     
  7. Aug 2, 2011 #6
    Is the answer 63.125 m?
     
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