# Displacement vecotrs

1. Sep 26, 2010

### EL ALEM

1. The problem statement, all variables and given/known data
Route follewed by hiker consists of displacement vectors A, B, C. Vector A is 1550 m long in a direction 25.0 N of E. Vector B is of unknown length but in a direction of 41.0 E of S. Vector C is also of unknown length but of direction 35.0 N of W. Hiker ends up where he started (A+B+C=0). Find magnitudes of B and C.

2. Relevant equations
Sine law: (a/sinA)=(b/sinB)=(c/SinC)

3. The attempt at a solution
Ok so i drew the triangle and figured out all of the interior angles:
A=14.0 degrees
B=60.0 degrees
C=106.0 degrees

Also i know side a=1550 m

I used the sin law to get
(a/sinA)=(b/sinB)
(1550/sin14)=(b/sin60)
b=(1550sin60/sin14)
b=5548.6477 m

(a/sinA)=(c/sinC)
(1550/sin14)=(c/sin106)
c=(1550sin106/sin14)
c=6158.829

I was just wondering if I did this right because the numbers look pretty big to me and would like someone to double check for me.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Sep 26, 2010

### EL ALEM

Anyone? Id like to know if there are any errors.

3. Sep 26, 2010

### D H

Staff Emeritus
Those numbers are correct.

4. Sep 26, 2010

### EL ALEM

Thanks a bunch