Find Force Applied Horizontally to Displace 0.06kg Bob 0.10m

  • Thread starter Yashbhatt
  • Start date
In summary, the problem involves finding the force required to move a 0.06 kg bob hanging on a 0.30 m string by 0.10 m. The solution involves using the equations F = mg and F = ma to calculate the value of SC, and then using this value to determine the forces acting on the bob in equilibrium. The hint suggests using the right triangle formed by the pendulum string to understand the direction of the forces.
  • #1
Yashbhatt
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Homework Statement


A bob weighing 0.06 kg hangs vertically at the end of a string 0.30m long. Find the force which when applied horizontally. will pull the bob 0.10m aside from it's initial position.


Homework Equations


F = mg, F = ma


The Attempt at a Solution


The solution in the book says:

In the figure, F = ma, CA = 1.10 m; SO = SA = 0.30 m.
SC = (SA2 - SC2)1/2 = 2√2 / 10 m

As, mg/SC = F / CA = T/AS and then the value is calculated. I don't understand what is done after obtaining the value of SC.
 

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  • #2
What has to be true for the bob to be in equilibrium? How can you relate the forces acting on the bob to the right triangle of which you just computed the sides?
Hint: the pendulum string can only provide a force in throuh the tension in it, which is directed in the string direction.
 

1. What is the formula for finding the force applied horizontally to displace a 0.06kg bob 0.10m?

The formula for finding force applied horizontally is F = m * a, where F is the force, m is the mass, and a is the acceleration.

2. How do you calculate the mass of a 0.06kg bob?

The mass can be measured using a scale or balance. Alternatively, it can be calculated by dividing the weight of the bob by the gravitational acceleration (9.8 m/s²).

3. What is the unit of measurement for force?

The unit of measurement for force is Newtons (N).

4. How do you determine the displacement of a 0.06kg bob?

The displacement of the bob can be measured using a ruler or tape measure, by noting the initial and final positions and calculating the difference.

5. Can you use this formula to find force applied in other directions?

No, this formula is specifically for finding the force applied horizontally. For other directions, different formulas must be used.

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