Does the inverse distribute over the group operation o?

  • Thread starter aeonstrife
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In summary, G is a group with respect to o, but it is not a group with respect to the operation # defined by x#y=(xoy)^-1. While the operation is closed, it is not clear if the inverse of (xoy) distributes over the group operation o, making it difficult to prove associativity for the operation #.
  • #1
aeonstrife
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G is a group with respect to o.

Another operation # is defined by x#y=(xoy)^-1

Show that G is not a group wrt #

I've gotten that the operation is closed but I can't figure out how to prove associativity because the inverse is a bit confusing.
 
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  • #2
How else can you write (xoy)-1?
 
  • #3
o is an operation. (xoy)^-1 is just the inverse of (xoy) if that makes sense
 
  • #4
I think what office shredder was asking is "Does the inverse distribute over the group operation o?" In other words, does (xoy)-1 = x-1oy-1 or does it equal something else?
 

What is a group?

A group is a mathematical structure consisting of a set of elements and a binary operation that combines any two elements of the set to form a third element. The operation must be associative, have an identity element, and have inverses for all elements in the set.

How do you prove that a set is a group?

To prove that a set is a group, you must show that the set and operation satisfy the four group axioms: associativity, identity, inverses, and closure. This can be done using algebraic manipulation and logical reasoning.

What does it mean to disprove a set is a group?

To disprove a set is a group means to show that the set and operation do not satisfy one or more of the four group axioms. This would mean that the set is not a valid mathematical group.

What are some common ways to disprove a set is a group?

Some common ways to disprove a set is a group include showing that the operation is not associative, the identity element does not exist, or not all elements have inverses. You can also disprove a set is a group by showing that the set is not closed under the operation.

Why is it important to disprove a set is a group?

It is important to disprove a set is a group because it ensures the validity and consistency of mathematical structures. If a set is mistakenly assumed to be a group, it can lead to incorrect conclusions and results in further mathematical reasoning.

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