17. (20 marks) A 0.410g sample of sodium fluoride is dissolved in 25.00mL of water and is then reacted with 50.00mL of 0.500mol/L calcium nitrate solution. After the mixture is filtered, 0.225g of precipitate is recovered. a ) Write the net ionic equation for the reaction which occurs. b) Calculate the maximum mass of precipitate that could be formed (theoretical yield). c) Calculate the percentage yield for this reaction. d) Calculate the concentrations of the three major ions in the final solution. https://ca.answers.yahoo.com/question/index?qid=20111210111858AA1ObOY For d) This website says :Mol Ca2+ remaining in solution: 0.025 mol Ca2+ initially - 4.88X10^-3 mol CaF2 formed = 0.0201 mol Ca2+ remaining / 0.075 L = 0.268 M Ca2+ My textbook answer says the same thing. BUT WHY! That is the result of theoretical maximum yield 100%... I get 0.294M using 0.225g. Can you back me up?