Distance between 2 particles

  • Thread starter mrkb80
  • Start date
  • #1
41
0

Homework Statement



The position of a particle at time t is given by r(t) = 3(t2 - sin t)i +
tj - (cos t)k , and the position of another particle is R(t) = t2i + (t3 +
t)j+(sin t)k . At time t = pi, what is the rate of change of the distance
between the two particles? Are they getting closer to one another, or
are they getting farther apart?


Homework Equations





The Attempt at a Solution



I'm actually not sure how to attempt this problem. I think that if the rate of change is postive they are getting farther apart and if it is negative they are getting closer, but I'm not sure.
 
Last edited by a moderator:

Answers and Replies

  • #2
hotvette
Homework Helper
996
5
The first thing you need to do is write an expression for the distance between the two particles. Think pythagorean theorem.
 
  • #3
41
0
I'm not sure I understand. Do I subtract the square of the i,j,k components from each other to get d^2 and then take the directional derivative?
 

Related Threads on Distance between 2 particles

  • Last Post
Replies
9
Views
409
E
  • Last Post
2
Replies
30
Views
2K
  • Last Post
Replies
7
Views
3K
  • Last Post
Replies
6
Views
7K
Replies
8
Views
5K
Replies
2
Views
1K
Replies
2
Views
1K
Replies
1
Views
5K
  • Last Post
Replies
4
Views
1K
  • Last Post
Replies
1
Views
560
Top