- #1

xyz_1965

- 76

- 0

Solution:

From R, I will drop a perpendicular to a point I call D. The distance between the two ships is PD + DQ.

To find PD:

tan (48°) = 3500/PD

PD = 3500/tan (48°)

PD = 3151.41 feet

To find DQ:

tan (25°) = 3500/DQ

DQ = 3500/tan (25°)

DQ = 7505.77 feet

Distance between the two ships:

PD + DQ = 3151.41 + 7505.77

PD + DQ = 10, 657.18

Rounded to the neatest 10th of a foot, I get

10,660 feet.

Is this correct? I hope so after all this work.