# Homework Help: Distance Block Slides Up Ramp

1. Apr 17, 2012

### getty102

1. The problem statement, all variables and given/known data
A block of mass 2.96 kg is sliding up a ramp with an initial speed of 12.8 m/s. The ramp is inclined from the horizontal at an angle of 36.4 degrees and the coefficient of kinetic friction is $\mu$=045. What is the displacement of the block along the ramp from the initial time until it stops?

2. Relevant equations

W=ΔE
W=∫F*ds
ΔE=(m/2)(vf)2-(m/2)(v0)2 where (vf)=0
$\Phi$=36.4
m=2.96kg
v0=12.8 m/s
$\mu$= 0.45

3. The attempt at a solution

$\mu$*m*g*cos$\Phi$x=-(m/2)(v0)2
solve for x
x=-(m/2)(v0)2/$\mu$*m*g*cos$\Phi$

2. Apr 17, 2012

### tiny-tim

hi getty102!

correct method, but you forgot to include the gravitational PE (or gravitational work done)

3. Apr 17, 2012

### getty102

Cool, thank you. The potential energy from gravity is dependent on the height. Which in this problem is kind of what I'm looking for because if I can find the height I would know the total displacement of the block up the ramp.

4. Apr 17, 2012

xsinΦ ?