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Homework Help: Distance covered on the moon

  1. Jan 22, 2014 #1
    1. The problem statement, all variables and given/known data

    A stone is thrown with an initial velocity 5m/s such that it covers maximum possible horizontal distance RE on the surface of the Earth. The same stone is thrown with same initial velocity by a person standing on the moon, making an angle of 150 with the surface. given that acceleration due to gravity on earth's surface is g=9.8m/s2 and that on moon's surface is gm=1.6m/s2, the horizontal distnace it covers on the moon is
    a) 0.326RE
    b) 0.326/RE
    c) 3.06RE
    d) -0.629RE

    2. Relevant equations


    3. The attempt at a solution

    so u2=2geRE
    Now, RM=u2sin215/gm
    substitute u2 in RM
    therefore RM=2geRE(0.067)/1.6
    after solving I get RM=RE(0.82)
    I know I'm missing the mark due to some stupid mistake somewhere, could you please point it out?
  2. jcsd
  3. Jan 22, 2014 #2
    Got it. I got the range formula wrong. the answer is c)
  4. Jan 22, 2014 #3


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    Homework Helper

    nice save :)
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