1. The problem statement, all variables and given/known data A stone is thrown with an initial velocity 5m/s such that it covers maximum possible horizontal distance RE on the surface of the Earth. The same stone is thrown with same initial velocity by a person standing on the moon, making an angle of 150 with the surface. given that acceleration due to gravity on earth's surface is g=9.8m/s2 and that on moon's surface is gm=1.6m/s2, the horizontal distnace it covers on the moon is a) 0.326RE b) 0.326/RE c) 3.06RE d) -0.629RE 2. Relevant equations RE=u2sin2θ/g 3. The attempt at a solution RE=u2/2ge so u2=2geRE Now, RM=u2sin215/gm substitute u2 in RM therefore RM=2geRE(0.067)/1.6 after solving I get RM=RE(0.82) I know I'm missing the mark due to some stupid mistake somewhere, could you please point it out?