Modifying a Car: 0-47 mph Distance Covered

[99precision]

First, I am not a student. I'm looking to do some modifications to a car and I'm not sure what to do.

Homework Statement

a 2.0 L, 4 cylinder engine w/ 146 hp

curb weight = 1418 kg

0-60 mph time of 8.6 s

0.25 mile time of 16.7 s at a top speed of 81.8 mph

What distance (miles) would be covered going from 0-47 mph?

Homework Equations

1 hour = 3600 s
60 mph = 0.0167 miles/s
47 mph = 0.013056 miles/s

The Attempt at a Solution

where do I go from here?

 

[Kurdt]

Assuming constant acceleration you will want to use the 1D kinematic equations.

https://www.physicsforums.com/showpost.php?p=905663&postcount=2

It might be handy to convert speed to metres per second.

A car however, does not undergo constant acceleration.

 

[baba89]

I cannot provide specific modifications for your car. However, I can offer some suggestions on how to approach this problem. First, it is important to understand the relationship between acceleration, time, and distance covered. This can be represented by the equation d= 1/2at^2, where d is distance, a is acceleration, and t is time.

Based on the given information, we can calculate the average acceleration of the car from 0-60 mph using the formula a= v/t, where v is velocity and t is time. This would give us an average acceleration of 6.98 m/s^2.

To determine the distance covered from 0-47 mph, we can use the formula d= 1/2at^2 again, but this time we will use the time it takes for the car to reach 47 mph, which is 8.6 seconds. Plugging in the values, we get a distance of approximately 163 meters or 0.101 miles.

It is important to note that these calculations are based on ideal conditions and do not take into account factors such as friction, air resistance, and other external forces that may affect the car's performance. Modifying a car can have a significant impact on its acceleration and speed, so it is important to consult with a professional and conduct thorough testing before making any modifications.