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Distance of a fallen object

  1. Oct 12, 2011 #1
    1. The problem statement, all variables and given/known data
    A stone is dropped from rest. Calculate the distance fallen during the first second. Calculate the distance fallen during the second second and third second, etc.

    2. Relevant equations
    d = (Vf^2 - Vo^2) / (2*a)


    3. The attempt at a solution
    a= 9.8 m/s^2
    ???
    I dont know what to do please help me solve this
     
  2. jcsd
  3. Oct 12, 2011 #2
    This equation may be more helpful.

    [tex] x = x_0 + v_0 t + (1/2) a t^2 [/tex]
     
  4. Oct 12, 2011 #3
    so
    x= 0+0+1/2(9.8)(1)^2
     
  5. Oct 12, 2011 #4
    Yes, that looks correct.
     
  6. Oct 12, 2011 #5
    Thank you !!!
     
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