A horse canters away from its trainer in a straight line, moving 140 m away in 14.0 s. It then turns abruptly and gallops halfway back in 4.3 s.(adsbygoogle = window.adsbygoogle || []).push({});

(a) Calculate its average speed. (m/s)

(b) Calculate its average velocity for the entire trip, using "away from the trainer" as the positive direction. (m/s)

To start, I have drawn a graph to represent this situation, with time on the x-axis and distance on the y-axis. 1) I don't know how average speed and average velocity are different (since I thought they were both how fast something is going, or the slope of the graph), and 2) I don't know how to find the derivative of the graph since it is not linear and I am given no additional information about the equation of the graph.

Maybe I am thinking way too far into this. I am new to physics, but I've had lots of math.

Thanks in advance for the help.

Wade

**Physics Forums - The Fusion of Science and Community**

# Distance/speed problem

Have something to add?

- Similar discussions for: Distance/speed problem

Loading...

**Physics Forums - The Fusion of Science and Community**