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Distributed Loads. Simple question

  1. Jan 9, 2012 #1
    Hi there,

    Parallel distributed loads are throwing me off a little at the moment. Is the resultant worked out the same way as for those with distributed loads perpendicular to a beam??

    Picture included.

    Thanks in advance

    Attached Files:

  2. jcsd
  3. Jan 9, 2012 #2
    lotsa views yet no help..

    please post a reply??
  4. Jan 9, 2012 #3


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    Gold Member

    An axial distributed load such as you've drawn would have a cumulative effect, so the force at the right end of the beam would be the sum of all forces to its left. In effect, you've drawn a force which increases with position from left to right.
    Last edited: Jan 9, 2012
  5. Jan 9, 2012 #4
    Thx :)
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