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Normal: mean = 0 standard deviation = 1

Is it:

10th percentile of standard normal distribution is -1.28

10th upper percentile of standard normal distribution is 0.1

90th percentile of standard normal distribution is -1.28

10th percentile of standard normal distribution is 1.28

The attempt at a solution

Area under the curve is the Population, at the center or x is the mean, let [tex]\alpha[/tex]/2 be the area shaded in red.

...lost. I know that in standard normal distribution N(mean, variance) = N(0,1) and to get the confidence interval = 1 - [tex]\alpha[/tex] = 0.1 which would be 90% (to the left)

I think it would be 10th upper percentile (to the right)

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# Homework Help: Distribution Plot

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