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**1. Homework Statement**

A diver with a snorkle can handle a pressure differential of 1/20 atmospheric pressure between his the oustide of his lungs and the inside. How deep can he dive? The water's density is 1025 kg/m^3.

**2. Homework Equations**

P=P_0+pgh

**3. The Attempt at a Solution**

I assumed P_atm = 101325 PA and the density of air is 1.29 kg/m^3.

I came up with P_(outside lungs)-P_(inside lungs)=(1/20)P_atm

P(outside lungs) = P_atm + pgh = 101325 + 1025*9.8*h

P(inside lungs) = P_atm + pgh = 101325 + 1.29*9.8*h

Solving for h I got 0.5 meters.... Just seems way to shallow.

**1. Homework Statement**

**2. Homework Equations**

**3. The Attempt at a Solution**