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Homework Statement
A diver with a snorkle can handle a pressure differential of 1/20 atmospheric pressure between his the oustide of his lungs and the inside. How deep can he dive? The water's density is 1025 kg/m^3.
Homework Equations
P=P_0+pgh
The Attempt at a Solution
I assumed P_atm = 101325 PA and the density of air is 1.29 kg/m^3.
I came up with P_(outside lungs)-P_(inside lungs)=(1/20)P_atm
P(outside lungs) = P_atm + pgh = 101325 + 1025*9.8*h
P(inside lungs) = P_atm + pgh = 101325 + 1.29*9.8*h
Solving for h I got 0.5 meters... Just seems way to shallow.