1. The problem statement, all variables and given/known data A high diver leaves the end pf a 5.0-m high diving board and strikes the water 1.3s later, 3.0m beyond the end of the board. Determine his inicial velocity, his maximum height and the velocity with which he enters water. (Projectile Motion). *See details at the end* 2. Relevant equations y = yo + vot + 1/2gt^2 3. The attempt at a solution I have worked on this exercise, and can fully answer it using the water as the origin with the y axis pointing upward. However, I wanted to try it with the diver leaving the board as the origin with the y-axis pointing downward (thus making g positive) and it's not giving me the correct result. Once I clear y = yo + vot + 1/2gt^2 for vo, I obtain vo = (y - yo + 1/2gt^2)/t. Since I am using the y-axis downward, I am making y = 5.00m and g = 9.8 m/s^2. I left the +1/2 gt^2 0 upon clearing the formula for vo since the acceleration is always downward (thus positive always). However, it's not giving me the right result. Someone see anything wrong with my logic? *I don't need help with the problem per-se, but with why the y component of velocity isn't giving me the right number. * The correct answer should be 2.5 i for the y component of vo.