- #1

- 1

- 0

[tex]

\vec \bigtriangledown \cdot \vec f ( \vec r ) = \frac {\partial}{\partial r} (r^2 | \vec f ( \vec r ) | )

[/tex]

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter avidfury
- Start date

- #1

- 1

- 0

[tex]

\vec \bigtriangledown \cdot \vec f ( \vec r ) = \frac {\partial}{\partial r} (r^2 | \vec f ( \vec r ) | )

[/tex]

- #2

Mute

Homework Helper

- 1,388

- 10

[tex]\frac{\partial}{\partial r}(r^2 |\mathbf{f}(\mathbf{r})|) = \frac{\partial}{\partial r}(r^2) = 2r[/tex]

[itex]\nabla \cdot \mathbf{f}(\mathbf{r}) = \partial_r(r^2|\mathbf{f}(\mathbf{r})|)[/itex] looks more like a differential equation to be solved rather than an identity.

Share:

- Replies
- 3

- Views
- 3K

Indirect Proof
(open) Divergent series of inverse primes

- Last Post
- Math Proof Training and Practice

- Replies
- 0

- Views
- 296