# Divergent Integral

## Homework Statement

I had to solve the integral....After all my work i got -infinity
3
integral sign 1/ [(t-3)^4/3]
1

## The Attempt at a Solution

-infinity....is this correct? and would this be divergent?

The expression

$$\frac{1}{(t - 3)^{4/3}}$$

is complex for $t < 3$.

Yes, it is divergent.

LeonhardEuler
Gold Member
It has a real root for t<3, so that's not a problem. I would check how you got the sign on that -$\infty$, though.