Dividing exponents

1. Jul 2, 2012

Gregory.gags

$\frac{(xa+b)a-b}{(xa-2b)a+2b}$

I figured since there is one addition and one subtraction of the same amounts in and out of the brackets, they would cancel each other out leaving just $\frac{x}{x}$ which would be 1 (or possibly x?) but I really have absolutely no idea.

also, and this is a long shot, I'm just guessing now that it could be something along the lines of...

$\frac{xa+b(a-b)}{xa-2b(a+2b)}$??

2. Jul 2, 2012

Gregory.gags

wow, I don't know why the fraction is like that but i hope you get what i'm trying to say :P (the left {} is the numerator and the right {} is the denominator )

3. Jul 2, 2012

Staff: Mentor

This last part is what you want to do, since (xa)b = xab.
The reason that your LaTeX expressions aren't rendering correctly is that (I believe) you are mixing in HTML stuff (SUP) with the LaTeX stuff. You're also missing some parentheses.

This is what you want.

$$\frac{x^{(a+b)(a-b)}}{x^{(a-2b)(a+2b)}}$$