A diving board of length L = 3.00 m is supported at a point a distance 1.00 m from the end, and a diver weighing 490 N stands at the free end. The diving board is of uniform cross section and weighs 295 N.(adsbygoogle = window.adsbygoogle || []).push({});

Find the force at the support point.

** Now I know net torque = 0

Suppose F1 is the force applied at the support point and F2 is the force at the end that is held down.

(F1*x_f1) - (w_diver * L) - (w_board * x_point) = 0

x_f1 = 3.0 m * {490 N/(490N + 295N)} = 1.87 m ?

--> F1(1.87 m) - (490 N)(3.0 m) - (295 N)(1.0 m) = 0 solve for F1

F1 = {(490N)(3.0 m) + (295N)(1.0 m)}/1.87 m = 944 N which is wrong

how do I find x_f1? is my formula for F1 correct?

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# Homework Help: Diving board

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